(3x-18)/(x+6)/(x^2-36)/(x^2+6x)

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Solution for (3x-18)/(x+6)/(x^2-36)/(x^2+6x) equation: 


D( x )

x^2-36 = 0

x+6 = 0

x^2+6*x = 0

x^2-36 = 0

x^2-36 = 0

1*x^2 = 36 // : 1

x^2 = 36

x^2 = 36 // ^ 1/2

abs(x) = 6

x = 6 or x = -6

x+6 = 0

x+6 = 0

x+6 = 0 // - 6

x = -6

x^2+6*x = 0

x^2+6*x = 0

x^2+6*x = 0

DELTA = 6^2-(0*1*4)

DELTA = 36

DELTA > 0

x = (36^(1/2)-6)/(1*2) or x = (-36^(1/2)-6)/(1*2)

x = 0 or x = -6

x in (-oo:-6) U (-6:0) U (0:6) U (6:+oo)

(((3*x-18)/(x+6))/(x^2-36))/(x^2+6*x) = 0

(3*x-18)/((x+6)*(x^2-36)*(x^2+6*x)) = 0

x^2+6*x = 0

x*(x+6) = 0

x+6 = 0 // - 6

x = -6

x*(x+6) = 0

(3*x-18)/(x*(x+6)^2*(x^2-36)) = 0

3*x-18 = 0 // + 18

3*x = 18 // : 3

x = 18/3

x = 6

x in { 6} 

x belongs to the empty set

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